Question

Question #5eb7d

Answer 1

11.7g

Explanation:

The molar mass of `NaCl=23+35.5=58.5g/"mol"`
Therefore
1L Or 1000mL 2M Solution contains 2mole solute.
Now 100 mL 2M solution will contain `2"mol"xx58.5g/"mol"xx(100L)/(1000L)=11.7g`
On evaporation 11.7g `NaCl` will be obtained as residue as it is non volatile solid of high mp.