What is the molarity of a 49.0*g49.0⋅g mass of phosphoric acid in a 2.00*L2.00⋅L volume of aqueous solution?

1 Answer
anor277
Sep 18, 2016

"Molarity"Molarity == "Moles of solute"/"Volume of solution"Moles of soluteVolume of solution

Explanation:

We get an answer with units mol*L^-1mol⋅L−1.

"Moles of phosphoric acid "(H_3PO_4)Moles of phosphoric acid (H3PO4) == (49.0*g)/(97.99*g*mol^-1)49.0⋅g97.99⋅g⋅mol−1 == 0.5*mol0.5⋅mol.

"Molarity"Molarity == (0.50*mol)/(2000*cm^3xx10^-3cm^3*L^-1)0.50⋅mol2000⋅cm3×10−3cm3⋅L−1

== 0.25*mol*L^-10.25⋅mol⋅L−1 with respect to H_3PO_4H3PO4.

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