Question

Question #284f8

Answer 1

4 moles of Aluminum

Explanation:

If we assume that we are creating Aluminum Chloride from the
metal-acid reaction between Aluminum and hydrochloric acid we can begin with the balanced chemical reaction below.

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

We can use the mole ratio `(2 mol Al)/(2 mol AlCl_3)`

The stoichiometry equation becomes

`4 mol AlCl_3 (2 mol Al)/(2 mol AlCl_3)`

`4 cancel(mol AlCl_3) (cancel2 mol Al)/(cancel2 cancel(mol AlCl_3))`

`= 4 mol Al`

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