Question #266c1

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Answer 1 · 2017-12-08T17:36:50

#x<= 43 #

We are trying to solve:

#log_5 3x-4 <= 3 #

Raising each of the sides by 5;

#5^(log_5 3x-4 ) <= 5^3 #

#=> 3x-4 <= 125 #

# => 3x <= 129#

Hence yielding:

#x<= 43 #