What volume would be occupied by a 0.1*mol0.1mol quantity of gas at a temperature of 310*K310K, and a pressure of 700*mm*Hg700mmHg?

1 Answer
Jul 25, 2017

Well, PV=nRTPV=nRT.........and so.......V~=3*LV3L

Explanation:

You must simply KNOW that 1*atm1atm pressure will support a column of mercury that is 760*mm760mm high; and thus "Torr"-=1*mm*HgTorr1mmHg stands in for a pressure measurement. You must also know the relationship between "degrees Kelvin"degrees Kelvin, and "degrees centigrade"degrees centigrade: 00 ""^@C-=+273.15*KC+273.15K

V=(nRT)/P=(0.1*molxx0.0821*(L*atm)/(K*mol)xx310*K)/((700*"Torr")/(760*"Torr"*atm^-1))V=nRTP=0.1mol×0.0821LatmKmol×310K700Torr760Torratm1

=??*L=??L. The question would have been better proposed had it been specified that 0.1*mol0.1mol quantity of gas had been enclosed in a piston at the given temperature and pressure.