Question #88621

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Answer 1 · 2016-06-11T14:51:09

$E=6.626\times10^-18$ J.

The energy of a photon, in quantum mechanics, is given by

$E=h\nu$ where $\nu$ is the frequency.
The relationship between frequency and wavelength is

$\nu=c/\lambda$ where $c$ is the speed of light and $\lambda$ is the wavelength.

So the energy, as function of the wavelength is

$E=(hc)/lambda$ .

It is now sufficient to substitute the numbers

$h=6.626\times10^-34$ $J*s$

$c=3\times10^8$ $m/s$

$\lambda=3*10^-8$ $m$

$E=(6.626\times10^-34*3\times10^8)/(3\times10^-8)$

$=6.626\times10^(-34+8+8)$

$=6.626\times10^-18$ J.