Question #2f910

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Question #2f910

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Answer 1 · 2016-07-16T11:27:21

$= \frac{13}{33}$ $=13/33$

Explanation:

$The length of the flag = 4 f t 6 inch = 4.5 f t$ $"The length of the flag "=4ft6"inch"=4.5ft"$

$The Breadth of the flag = 2 f t 9 inch = 2.75 f t$ $"The Breadth of the flag "=2ft9"inch"=2.75ft$

$The width of the blue cross = 9 inch = 0.75 f t$ $"The width of the blue cross "=9"inch"=0.75ft$

$The area of blue cross = ((4.5 + 2.75) \times 0.75 - {(0.75)}^{2}) f t^{2}$ $"The area of blue cross"=((4.5+2.75)xx0.75-(0.75)^2)"ft^2$
$= 4.875 f t^{2}$ $=4.875ft^2$

$Total area of the flag = 4.5 \times 2.75 f t^{2} = 12.375 f t^{2}$ $"Total area of the flag"=4.5xx2.75ft^2=12.375ft^2$

So

$Fraction occupied by the blue cross = \frac{4.875}{12.375} = \frac{13}{33}$ $"Fraction occupied by the blue cross"=4.875/12.375=13/33$

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Question #2f910

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