Question #3419a

1 Answer
Jul 6, 2016

(a) 460.0N, rounded to one decimal place.
(b) 372.6N, rounded to one decimal place.

Explanation:

my computer
The figure above shown the position of the force vector whose x and y components are to be resolved.
(a) the x scalar component F_x=Fcos 39^@
Inserting value of cos from tables
=>F_x=Fxx0.7771= 592xx0.7771
=460.0N, rounded to one decimal place.

(b) y scalar component of the vector F_y=-Fsin 39^@
(-ve sign has been placed in front as the angle is in the fourth quandrant or F_y is in the -y direction).
Inserting value of sin from tables
=>F_y=Fxx0.6293=592xx0.6293
= 372.6N, rounded to one decimal place.