Question #9ef93

1 Answer
Jun 17, 2016

f'(x)=4(2x-6)^3*2(x^2+1)^5+(2x-6)^4*5(x^2+1)^4*2x

Explanation:

assume exist f(x)=(2x-6)^4(x^2+1)^5
use chain rule
d/dx(2x-6)^4=4(2x-6)^3d/dx(2x-6)=4(2x-6)^3*2
same concept
d/dx(x^2+1)^5=5(x^2+1)^4*2x

f'(x)=4(2x-6)^3*2(x^2+1)^5+(2x-6)^4*5(x^2+1)^4*2x