Question #9a12e

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Answer 1 · 2016-09-25T12:08:03

$M(x/2 ; (y-3)/2)$

The midpoint is found from finding:

"The average of the x-values and the average of the y-values"

As a formula : $M((x_1+x_2)/2 ; (y_1+y_2)/2)$

From the given points $V(-2,-6) and W(x+2, y+3)$

$M((-2+x+2)/2 ; (-6+y+3)/2)$

$M(x/2 ; (y-3)/2)$

Answer 2 · 2016-09-25T12:12:19

Midpoint Formula for two points $(x_1,y_1) and (x_2,y_2)$ is as follows
$((x_1 + x_2)/2 , (y_1 + y_2)/2)$

Something like you're averaging the two points' $x$ - and $y$ -values.

Inserting given values we get the coordinates of the midpoint as
$((-2 + (x+2))/2 , (-6 + (y+3))/2)$
$=>(x/2 , ( y-3)/2)$