Question #88f84

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Question #88f84

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Answer 1 · 2016-07-20T21:48:10

We need to calculate both sides of the equation, and find a value $c$ that satisfies it

Explanation:

We calculate first $f(2)=2*2^2-3*2+1=3$
We then calculate $f(0)=2*0^2-3*0+1=1$

We then calculate $(f(2)-f(0))/(2-0)=(3-1)/(2-0)=1$

We calculate now $f'(x)=4x-3$ , and now we need to find a point $c$ where $f'(c)=1$ , that is $4c-3=1$ , but this means $4c=4$ , and hence $c=1$ is the value we are looking for

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Question #88f84

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