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Question #31f5d

1 Answer

Aug 9, 2016

$y = x + 1$ $y=x+1$

Its gradient Is $m = 1$ $m=1$

Explanation:

Given -

$x_{1} = 1$ $x_1=1$
$y_{1} = 2$ $y_1=2$
$x_{2} = 5$ $x_2=5$
$y_{2} = 6$ $y_2=6$

The equation is -

$(y - y_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$

$(y - 2) = \frac{6 - 2}{5 - 1} (x - 1)$ $(y-2)=(6-2)/(5-1)(x-1)$
$y - 2 = \frac{4}{4} (x - 1)$ $y-2=4/4(x-1)$
$y - 2 = 1 (x - 1)$ $y-2=1(x-1)$
$y = x - 1 + 2$ $y=x-1+2$
$y = x + 1$ $y=x+1$

Its gradient Is $m = 1$ $m=1$

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