What is the mass concentration of $0.05 N$ $"0.05 N"$ $HCl$ $"HCl"$ ?

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What is the mass concentration of $0.05 N$ $"0.05 N"$ $HCl$ $"HCl"$ ?

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Answer 1 · 2016-08-18T22:27:49

Normally (pun intended?), normality would tell you the equivalent concentration of protons for a given acid. So if you had $1 M$ $"1 M"$ $H_{2} {SO}_{4}$ $"H"_2"SO"_4$ , it would actually be $2 N$ $"2 N"$ $H_{2} {SO}_{4}$ $"H"_2"SO"_4$ , since there are two protons per molecule of $H_{2} {SO}_{4}$ $"H"_2"SO"_4$ .

However, since $HCl$ $"HCl"$ is monoprotic, $0.05 N HCl$ $"0.05 N HCl"$ $=$ $=$ $0.05 M HCl$ $"0.05 M HCl"$ .

Therefore, you should have $\frac{0.05 mols HCl}{L soln}$ $"0.05 mols HCl"/"L soln"$ , or:

$"0.05" cancel"mols HCl" xx "36.4609 g HCl"/cancel"1 mol HCl"$

$= color(blue)("1.82 g HCl"/"L soln")$

Even though $0.05$ has only one sig fig, realistically you could easily measure at least to the hundredths place for the mass, so you can have more like $"0.0500 M HCl"$ .

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What is the mass concentration of $0.05 N$ $"0.05 N"$ $HCl$ $"HCl"$ ?

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