Question

Question #19f25

Answer 1

ln|(e^x-e^-x)|+C#.

Explanation:

Let `e^x-e^-x=t rArr {e^x-(-e^-x)}dx=dt`.

`rArr (e^x+e^-x)dx=dt`

Hence, `I=int(e^x+e^-x)/(e^x-e^-x)dx=intdt/t=ln|t|=ln|(e^x-e^-x)|+C`.