Question #e4efb

1 Answer
Cesareo R.
Oct 12, 2017

int sinx/sin(x+a) dx = (x+a)cosa-log(sin(x+a))sina + C

Explanation:

Making y = x+a and dy = dx we have

int sinx/sin(x+a) dx = int sin(y-a)/siny dy = int (cosa - cos y/siny sina)dy = y cosa-log(siny) sina + C

and finally

int sinx/sin(x+a) dx = (x+a)cosa-log(sin(x+a))sina + C

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