To make a $0.10 \cdot L$ $0.10L$ volume of $[N a O H] (a q) = 0.15 \cdot m o l \cdot L^{- 1}$ $[NaOH](aq)=0.15mol*L^-1$ , what mass of sodium hydroxide is required?

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To make a $0.10 \cdot L$ $0.10L$ volume of $[N a O H] (a q) = 0.15 \cdot m o l \cdot L^{- 1}$ $[NaOH](aq)=0.15mol*L^-1$ , what mass of sodium hydroxide is required?

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Answer 1 · 2016-08-09T15:34:36

Approx. $600 \cdot m g$ $600*mg$

Explanation:

$Moles of sodium hydroxide$ $"Moles of sodium hydroxide"$ $=$ $=$ $0.100*cancelLxx0.15*mol*cancel(L^-1)$ $=$ $0.015*mol$

$"Mass of sodium hydroxide"$ $=$ $0.015*cancel(mol)xx40.00*g*cancel(mol^-1)$ $=$ $??g$

It would be hard to measure such a mass of sodium hydroxide accurately inasmuch as the stuff is deliquescent, and absorbs atmospheric moisture readily. It would be better to make a solution of the approximate concentration, and then make an accurate determination of $[NaOH]$ with standardized acid.

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To make a $0.10 \cdot L$ $0.10L$ volume of $[N a O H] (a q) = 0.15 \cdot m o l \cdot L^{- 1}$ $[NaOH](aq)=0.15mol*L^-1$ , what mass of sodium hydroxide is required?

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To make a 0.10*L0.10⋅L0.10*L volume of [NaOH](aq)=0.15*mol*L^-1[NaOH](aq)=0.15⋅mol⋅L−1[NaOH](aq)=0.15*mol*L^-1, what mass of sodium hydroxide is required?

1 Answer

Explanation:

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To make a $0.10 \cdot L$ $0.10L$ volume of $[N a O H] (a q) = 0.15 \cdot m o l \cdot L^{- 1}$ $[NaOH](aq)=0.15mol*L^-1$ , what mass of sodium hydroxide is required?