$18.9g$ of ammonium nitrate is dissolved in a $855mL$ volume of water. What is the concentration of the salt?

Question

2951 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-11T19:46:52

$"Molarity"="Moles of solute"/"Volume of solution"$

And thus $"molarity"$ $=$ $((18.9*g)/(80.04*g*mol^-1))/(0.855*L)$ $=$ $??*mol*L^-1$ .

18.9*g18.9*g of ammonium nitrate is dissolved in a 855*mL855*mL volume of water. What is the concentration of the salt?