Question

Question #bbc92

Answer 1

Let w gram of `KIO_3` be dissolved in water to make a solution V L.

Now molar mass of `KIO_3=39+127+3*16=214g/"mol"`

So w g `KIO_3="w g"/(214g/"mol")=w/214mol`

So the strength of this solution will be
`="no of moles of solute"/"Volume"xx1000M`

`=w/(214V)xx1000M =S (M)`

The no of moles of solute present xL solution will be `x xxS" mol"`

As the solute `KIO_3` is a strong electrolyte which dissociates in water as follows , the solution will contain same no. of moles of `IO_3^-` ions as it contains no.of moles of `KIO_3`

`KIO_3rightleftharpoonsK^+ + IO_3^-`