What mass of ammonia constitutes a volume of $22.4*dm^3$ at $"STP"$ ?

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Answer 1 · 2016-08-15T19:48:36

$22.4*dm^3$ of ammonia at $"STP"$ specifies a mole of ideal gas............

So if we treat ammonia as an ideal gas, there are $(14.01+3xx1.00794)*g$ of $NH_3(g)$

What mass of ammonia constitutes a volume of 22.4*dm^322.4*dm^3 at "STP""STP"?