If #[H_3O^+]=7.5xx10^-3molL^-1#, what is #pH#?

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Answer 1 · 2016-08-17T04:17:57

#pH=-log_10[H_3O^+]# #=##-(-2.13)# #=# #2.13#

By definition #pH# #=# #-log_10[H_3O^+]#

And #-log_10[7.5xx10^-3]# #=# #-(-2.13)#

#=# #2.13#

If #[H_3O^+]=7.5xx10^-3*mol*L^-1#, what is #pH#?