If $[H_3O^+]=7.5xx10^-3molL^-1$ , what is $pH$ ?

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Answer 1 · 2016-08-17T04:17:57

$pH=-log_10[H_3O^+]$ $=$ $-(-2.13)$ $=$ $2.13$

By definition $pH$ $=$ $-log_10[H_3O^+]$

And $-log_10[7.5xx10^-3]$ $=$ $-(-2.13)$

$=$ $2.13$

If [H_3O^+]=7.5xx10^-3*mol*L^-1[H_3O^+]=7.5xx10^-3*mol*L^-1, what is pHpH?