Question #e56a2

Question

1672 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-21T10:11:22

The Reqd. Value $=1$ .

Given that, $a+b+c=0 rArr c=-a-b$

Sub.ing,. this value of $c$ in the given expression, we have,

The Exp. $=1/(x^b+x^(a+b)+1)+1/(x^(-a-b)+x^-a+1)+1/(x^a+x^-b+1)$

$=1/(x^b+x^(a+b)+1)+1/(1/(x^(a+b))+1/x^a+1}+1/{x^a+(1/x^b)+1}$

$=1/(x^b+x^(a+b)+1)+x^(a+b)/(1+x^b+x^(a+b))+x^b/(x^(a+b)+1+x^b)$

$=(1+x^(a+b)+x^b)/(1+x^(a+b)+x^b)$

$=1$ .

Hence, the Reqd. Value $=1$ .

Enjoy Maths.!