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Answer 1 · 2016-08-27T09:24:50

It is assumed that the given reaction is a gaseous one as it deals with $K_p$ and the reversible reaction is represented by the following equation

$H_2(g)+I_2(g)rightleftharpoons2HI$

We know that the relation between $K_p and K_c$ of agaseous reaction is

$K_p=K_c(RT)^(Deltan)....(1)$

Where $T->"Temperayure of the reaction in Kelvin"$

$R->"Universal gas constant"$

$Deltan->"Total no. of moles of gaseous product"- "Total no. of moles of gaseous reactants"$

For the given reaction

$Deltan=n_(HI(g))-n_(H_2(g))-n_(I_2(g))=2-1-1=0$

So by equation(1)

$K_p=K_c(RT)^(Deltan)=K_c(RT)^0=K_c=50$