Question

What is the net ionic equation for the double replacement reaction between sodium sulfate and barium nitrate?

Answer 1

See explanation

Explanation:

`Na_2SO_4(aq)+ Ba(NO_3)_2(aq)->BaSO_4(s)+2NaNO_3(aq)`

Break up the compounds into ions from which they came and cross out the ones that appear on both sides; those are your `"spectator ions"`.

`2 cancel(Na^(+)(aq)) + SO_4^(2-)(aq) + Ba^(2+)(aq) +2 cancel (NO_3^(-)(aq))->BaSO_4(s) darr + 2 cancel(Na^(+)(aq)) +2 cancel(NO_3^(-)(aq))`

`"Barium sulfate"` is insoluble so it doesn't ionize in solution

Write net ionic equation

`SO_4^(2-)(aq) + Ba^(2+)(aq) -> BaSO_4(s) darr`