How many $"kg"$ of $"C"$ atom are in $"3.6 mols"$ of $"C"$ atom?

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Answer 1 · 2016-09-01T01:15:44

0.043 kg C.

3.6 mol C * $(12.01 g C)/(1 mol C)$ = 43.236 g C

43.236 g C * $(1 kg)/(1000 g)$ = 0.043 kg C

You only need the 6.022 when converting to molecules.

How many "kg""kg" of "C""C" atom are in "3.6 mols""3.6 mols" of "C""C" atom?