If I have 9.71×1022 platimum atoms, what molar quantity, and what mass of metal are present?

1 Answer
anor277
Sep 1, 2016

You have approx 0.16⋅mol of platinum atoms, with a mass of approx. 30⋅g.

Explanation:

Moles of platinum = 9.71×1022⋅platinum atoms6.022×1023⋅platinum atoms⋅mol−1 = ??moles?

Now 1 mol of Pt atoms has a mass of 195.08⋅g.

So you should have a mass of approx. 30⋅g.

I appreciate that it is hard to work with such unfeasibly large numbers. But remember that the mole is just another number, like a score, or a dozen, or 1 gross - it's just that a mole is *&&??! LARGE. Avogadro's number of platinum atoms specifies 1 mol and has a mass of 195.08⋅g. Likewise Avogadro's number of 1H atoms has a mass of 1⋅g precisely.

This idea of molar and mass equivalence is something that is fundamental to chemistry, and you should take some effort to appreciate it.

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