Evaluate $tan^(-1) tan((7pi)/8)$ ?

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Answer 1 · 2017-07-14T12:37:35

$(7pi)/8$
[Assuming question was $tan^-1tan((7pi)/8)$ ]

Obviously this question lacks complete definition, but it seems reasonable that what was intended was: $tan^-1tan((7pi)/8)$

Then, we should consider: $f^-1(x) xx f(x) = x$

So, in this example: $tan^-1tan((7pi)/8) = (7pi)/8$

Evaluate tan^(-1) tan((7pi)/8)tan^(-1) tan((7pi)/8) ?