How do you solve $d - 4 \leq \frac{13 - d}{3}$ $d-4 <= (13-d)/3$ ?

Question

How do you solve $d - 4 \leq \frac{13 - d}{3}$ $d-4 <= (13-d)/3$ ?

1 Answer

Impact of this question

1433 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-13T19:29:27

$d \leq \frac{25}{4}$ $d <= 25/4$

Explanation:

If I read it correctly - upside down - this is an inequality:

$d - 4 \leq \frac{13 - d}{3}$ $d-4 <= (13-d)/3$

First multiply both sides by $3$ $3$ to get:

$3 d - 12 \leq 13 - d$ $3d-12 <= 13 - d$

Add $d + 12$ $d+12$ to both sides to get:

$4 d \leq 25$ $4d <= 25$

Divide both sides by $4$ $4$ to get:

$d \leq \frac{25}{4}$ $d <= 25/4$

Any $d$ $d$ satisfying the original inequality will satisfy this final one and since all of these operations are reversible, any $d$ $d$ satisfying this final inequality will satisfy the original one.

Science

Math

Humanities

... and beyond

How do you solve $d - 4 \leq \frac{13 - d}{3}$ $d-4 <= (13-d)/3$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve d−4≤13−d3d-4 <= (13-d)/3 ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $d - 4 \leq \frac{13 - d}{3}$ $d-4 <= (13-d)/3$ ?