How is $"cuprous ion"$ oxidized by bleach to give $"cupric ion"$ ?

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Answer 1 · 2016-09-11T07:48:38

This is a redox reaction; cuprous ion is oxidized by bleach to cupric ion.

$ClO^(-) +2H^(+) + 2e^(-) rarr Cl^(-) + H_2O(l)$ , $"reduction"$

$Cu^(+) rarr Cu^(2+) + 1e^(-)$ , $"oxidation"$

$2Cu^(+) + ClO^(-) +2H^(+)rarr 2Cu^(2+) + Cl^(-) + H_2O(l)$ .

Charge and mass are balanced, so this equation is reasonable.

How is "cuprous ion""cuprous ion" oxidized by bleach to give "cupric ion""cupric ion"?