How many $nanometres$ $"nanometres"$ in $7.5 \cdot μ m$ $7.5*mum$ ?

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Answer 1 · 2016-09-11T20:50:33

$7500$ $7500$ $n m$ $nm$

$1$ $1$ $μ m$ $mum$ $=$ $=$ $1 \times 10^{- 6} m$ $1xx10^-6m$

$1$ $1$ $n m$ $nm$ $=$ $=$ $1 \times 10^{- 9} m$ $1xx10^-9m$

$7.5 \cdot μ m = 7.50 \times 10^{- 6} m \times 10^{9} n m \cdot m^{- 1}$ $7.5*mum=7.50xx10^-6mxx10^9nm*m^-1$ $=$ $=$ $7500 \cdot n m$ $7500*nm$ .

How many "nanometres"nanometres"nanometres" in 7.5*mum7.5⋅μm7.5*mum?