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Question #57221

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Sep 14, 2016

$0.2$ $0.2$ $moles$ $"moles"$ of salt are present.

Explanation:

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles}{Volume of solution}$ $"Moles"/"Volume of solution"$ .

And thus, $Moles$ $"Moles"$ $=$ $=$ $Concentration \times Volume$ $"Concentration "xx" Volume"$ .

And $1*cancelLxx0.200*mol*cancel(L^-1)$ $=$ $0.2*mol$ .

How many grams of sodium chloride are there in this molar quantity?

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