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Answer 1 · 2017-07-20T19:07:36

#(6,3);(12,4);(18,5)#

The equation shows how to calculate a value for #y# if you know a value for #x#. You can find any number of ordered pairs.

You can CHOOSE any value for #x# and then calculate the corresponding value of #y#.

I would suggest choosing multiples of #6# to make the dividing easier.

Choose #x= 6, 12, 18#

#y = 1/6(6)+2 = +=1+2 =3" "rarr (6,3)#

#y = 1/6(12)+2 = 2+2=4" "rarr (12,4)#

#y = 1/6(18)+2 = 3+2 =5" "rarr (18,5)#