Question #37b65

1 Answer
Nov 4, 2016

First expression

=sintan^-1(x/3)

=sincot^-1(3/x)

=sincsc^-1sqrt(1+(3/x)^2)

=sincsc^-1sqrt((x^2+9)/x^2)

=sinsin^-1sqrt(x^2/(x^2+9))

=x/sqrt((x^2+9))

2nd expression

=sin(2tan^-1(x/3))

=(2tantan^-1(x/3))/(1+(tantan^-1(x/3))^2)

=((2x)/3)/(1+x^2/9)=(6x)/(9+x^2)