Question #9451d

1 Answer
P dilip_k
Sep 18, 2016

Given that the vectors have same length, it is meant that they have same magnitude. Let this be a and angle between them is thetaθ. By the problem the resultant of the two being twice of either i.e. 2a, we can write

(2a)^2=a^2+a^2+2xxaxxacostheta(2a)2=a2+a2+2×a×acosθ

=>costheta=1=>theta =0^@⇒cosθ=1⇒θ=0∘

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