Question #59964

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Question #59964

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Answer 1 · 2016-09-24T01:55:54

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Explanation:

The Lewis dot structure of Methoxymethane

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$The electronic configuration of oxygen \to 1 s^{2} 2 s^{2} 2 p_{x}^{2} 2 p_{y}^{1} 2 p_{z}^{1}$ $"The electronic configuration of oxygen "->1s^2 color(red)(2s^2 2p_x^2) 2p_y^1 2p_z^1$
The Oxygen atom has two unpaired and two lone pairs of electrons in the valence shell.The two unpaired electrons form two $σ$ $sigma$ -bond with two C-atoms of two $C H_{3}$ $CH_3$ group leaving behind two lone pairs of electrons.

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Question #59964

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