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Answer 1 · 2018-01-02T11:41:17

268 cows plus 335 calves

x number of cows that have only one calf
(268-x) is number of cows that have two calves.

$x + (268 - x) \times 2 = 335$ $x + (268-x)times2 = 335$

$x + 536 - 2 x = 335$ $x + 536 - 2x = 335$

$- x = 335 - 536$ $-x = 335-536$

$x = 201$ $x = 201$

Therefore, there are 67 cows that have two calves each.

The fraction of cows that have only one calve:

$\frac{100 \times 201}{268} = 75$ $(100times201)/268 = 75$ percent.

$25 %$ $25%$ of cows have two calves.