Question #9ee2e

Question

Question #9ee2e

1 Answer

Impact of this question

1795 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-29T08:47:24

We know molar mass of Hydrogen is $= 2 \frac{g}{mol}$ $=2g/"mol"$

The amount of hydrogen given is $= 4.47 \times 10^{- 4} g = \frac{4.47 \times 10^{- 4} g}{2 \frac{g}{mol}}$ $=4.47xx10^-4g= (4.47xx10^-4g)/(2g/"mol")$
$= 2.235 \times 10^{- 4} m o l$ $=2.235xx10^-4mol$

The equation of the reaction

$N_{2} + 3 H_{2} \to 2 N H_{3}$ $N_2 + 3H_2 -> 2NH_3$

As per this equation

3 moles $H_{2}$ $H_2$ produces 2 moles $N H_{3}$ $NH_3$

So
$2.235 \times 10^{- 4} m o l$ $2.235xx10^-4mol$ H_2 will

produce $\frac{2}{3} \times 2.235 \times 10^{- 4} m o l N H_{3}$ $2/3xx2.235xx10^-4mol NH_3$

$= \frac{2}{3} \times 2.235 \times 10^{- 4} \times 6.023 \times 10^{23} molecules N H_{3}$ $=2/3xx2.235xx10^-4xx6.023xx10 ^23 " molecules "NH_3$

$\approx 8.97 \times 10^{23} molecules N H_{3}$ $~~8.97xx10^23 " molecules " NH_3$

Science

Math

Humanities

... and beyond

Question #9ee2e

1 Answer

Related questions

Impact of this question