What mass of iron is present in a $100*g$ mass of $"ferric oxide"$ ?

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Answer 1 · 2016-09-26T16:17:47

Approx. $70*g$ .

The molecular mass of $"ferric oxide, "Fe_2O_3$ is $159.69*g*mol^-1$ .

$"Moles of ferric oxide"$ $=$ $"Mass"/"Molar mass"$ $=$ $(100*g)/(159.69*g*mol^-1)$ $=$ $0.626*mol$

And thus in a $100*g$ sample there are $2xx0.626*molxx55.85*g*mol^-1$ of iron metal.

And thus iron content $=$ $0.626*molxx2xx55.85*g*mol^-1$

$=$ $??g$ .

What mass of iron is present in a 100*g100*g mass of "ferric oxide""ferric oxide"?