Find coordinates of the point, which when joined with (c_1,c_2) forms a line that is parallel to the line joining (a_1,a_2) and (b_1,b_2)?

1 Answer
Sep 26, 2016

Any point lying on (b_2-b_1)(x-c_1)-(y-c_2)(a_2-a_1)=0 when joined with (c_1,c_2) would form a line parallel to the line joining (a_1,a_2) and (b_1,b_2).

Explanation:

The slope of a line passing through (a_1,a_2) and (b_1,b_2) is (b_2-b_1)/(a_2-a_1)

The equation of a line with a slope m and passing through (x_1,y_1) is y-y_1=m(x-x_1)

As the slope of the line parallel to above too would be (b_2-b_1)/(a_2-a_1) and as it passes through (c_1,c_2), its equation would be

y-c_2=(b_2-b_1)/(a_2-a_1)(x-c_1) or

(b_2-b_1)(x-c_1)-(y-c_2)(a_2-a_1)=0

Hence any point lying on (b_2-b_1)(x-c_1)-(y-c_2)(a_2-a_1)=0 will satisfy the given condition, i.e. when joined with (c_1,c_2) would form a line parallel to the line joining (a_1,a_2) and (b_1,b_2).