How much iron metal can be prepared from an $100*kg$ mass of $"ferric oxide"$ , and excess carbon monoxide?

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Answer 1 · 2016-09-30T19:18:40

$Fe_2O_3(s) + 3CO(g) rarr 2Fe(s) + 3CO_2(g)$

Approx $70*kg$ of iron metal can be produced.

$"Moles of ferric oxide"$ $=$ $(100*cancel(kg)xx10^3*cancelg*cancel(kg^-1))/(159.69*cancelg*mol^-1)$ $=$ $626.2*mol$ .

And clearly, from the stoichiometry of the reaction, $2xx626.2*cancel(mol)xx55.85*cancelg*cancel(mol^-1)xx10^-3kg*cancel(g^-1)$ $=$ $??$

How much iron metal can be prepared from an 100*kg100*kg mass of "ferric oxide""ferric oxide", and excess carbon monoxide?