How do you simplify? $\frac{v^{0} \cdot w^{0}}{v \cdot w^{0} \cdot v^{- 1} \cdot w^{4}}$ $(v^0 * w^0)/(v * w^0 * v^(-1) * w^4)$

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Answer 1 · 2016-10-06T17:24:18

$\frac{1}{w^{4}}$ $1/w^4$

$\frac{v^{0} \cdot w^{0}}{v \cdot w^{0} \cdot v^{- 1} \cdot w^{4}}$ $(v^0 * w^0)/(v * w^0 * v^(-1) * w^4)$

There are several law of indices which we can use here.

$x^{0} = 1 (x \neq 0)$ $x^0 = 1 (x!=0)" "$ and $x^{m} \times x^{n} = x^{m + n}$ $" "x^m xx x^n = x^(m+n)$

$x^{- m} = \frac{1}{x^{m}}$ $x^-m = 1/x^m" "$ Also recall: $\frac{x}{x} = 1 (x \neq 1)$ $x/x=1 (x!=1)$

$(cancel(v^0)1 * cancel(w^0)1)/(v * cancel(w^0) * v^(-1) * w^4)" "larr v^(1-1) = v^0 = 1$

$1/(cancel(v^0)1*w^4)$

$1/w^4$

How do you simplify? (v^0 * w^0)/(v * w^0 * v^(-1) * w^4)v0⋅w0v⋅w0⋅v−1⋅w4(v^0 * w^0)/(v * w^0 * v^(-1) * w^4)