Question

Question #66db7

Answer 1

The solution contains 60% (w/w) solute and its density is `2" g/cc"`

This means 100g solution which has volume `(100g)/(2g/"cc")= 50 c c` or 50mL will contain 60g solute.

So 1000mL 0r 1L solution contain `(60xx1000)/50g=1200g` solute
Molar mass of solute `80" g/mol"`

So molarity of the solution`="Strength in g/L"/"molar mass"`

`=(1200g/L)/(80g/"mol")=15M`