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Question #aeea4

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Oct 11, 2016

$\frac{x - (\frac{4}{x})}{(\frac{x}{2}) - (\frac{x - 1}{3})}$ $(x-(4/x))/((x/2)-((x-1)/3))$

$= \frac{(\frac{x^{2} - 4}{x})}{(\frac{3 x - 2 x + 2}{6})}$ $=(((x^2-4)/x))/(((3x-2x+2)/6))$

$= \frac{\frac{(x - 2) (x + 2)}{x}}{(\frac{x + 2}{6})}$ $=(((x-2)(x+2))/x)/(((x+2)/6))$

$= \frac{6 (x - 2) (x + 2)}{(x) (x + 2)}$ $=(6(x-2)(x+2))/((x)(x+2))$

$= \frac{6 (x - 2)}{x}$ $=(6(x-2))/(x$

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