Question

Question #bb39f

Answer 1

Molar mass of
`CuNO_3=(63.5+14+3*16)=125.5" g/mol"`

The amount of `CuNO_3=6.58g=(6.58g)/(125.5g/"mol")`
`=0.052mol`

If the volume of the solution be VL,then its strength `=0.052/VM`

Given strength is 0.15M

By the problem

`0.052/V=0.15`

`=>V=0.052/0.15L=0.3467L=346.7L`