What mass of sodium chloride is present in a $250 \cdot m L$ $250mL$ volume of $5.0 \cdot m o l \cdot L^{- 1}$ $5.0mol*L^-1$ $N a C l (a q)$ $NaCl(aq)$ ?

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Answer 1 · 2016-10-15T16:32:09

$Mass of NaCl ≅ 75 \cdot g$ $"Mass of NaCl"~=75*g$

We use the relationship:

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution}$ $"Moles of solute"/"Volume of solution"$

We know $Concentration$ $"Concentration"$ and $Volume$ $"Volume"$ , and thus

$Moles of solute$ $"Moles of solute"$ $=$ $=$ $Concentration \times Volume of solution$ $"Concentration"xx"Volume of solution"$

$=$ $=$ $5.0*mol*cancel(L^-1)xx250*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)$

$=$ $1.25*mol$

And a $1.25*mol$ quantity of sodium chloride has a mass of $1.25*cancel(mol)xx58.44*g*cancel(mol^-1)$ $=$ $??*g$

What mass of sodium chloride is present in a 250*mL250⋅mL250*mL volume of 5.0*mol*L^-15.0⋅mol⋅L−15.0*mol*L^-1 NaCl(aq)NaCl(aq)NaCl(aq)?