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Answer 1 · 2016-10-14T03:55:12

Molar mass of Hydrogen $=2" g/mol"$
Amount of Hydrogen to be produced

$=10g =(10g)/(2g/"mol")=5mol$

Reaction used

$Zn+2HNO_3->Zn(NO_3)_2+H_2$

This equation reveals that 1 mol Hydrogen is produced if 2 mol $HNO_3$ is reacted with excess Zn.

To produce 10g or 5 mol $H_2$ we require $5xx2=10" mol "HNO_3$

This amount of $HNO_3$ can be obtained from 2M solution having volume $V=(10mol)/(2"mol"/L)=5L$