How many carbon atoms in a $3.25*"carat"$ diamond?

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Answer 1 · 2016-10-16T06:30:09

$"Number of carbon atoms"$ $=$ $0.054*molxx6.022xx10^23*mol^-1$ $=$ $??$

$"1 carat"$ $=$ $"200 mg"$

$"Number of moles"$ $=$ $"Mass"/"Molar mass"$

$"Number of moles of carbon"$

$=$ $(3.25 cancel" carat"xx200xx10^-3*cancelg*cancel"carat"^-1)/(12.011*cancelg*mol^-1)$

$=$ $0.054*mol$ , and we mulitply this by $"Avogadro's number"$ to get the number of carbon atoms.

$"Number of carbon atoms"$ $=$ $0.054*molxx6.022xx10^23*mol^-1$ $=$ $??$

And we go thru the same process for the aspirin sample:

$(0.75*g)/(180.16*g*mol^-1)xx6.022xx10^23*mol^-1$ $=$

$"How many aspirin molecules?"$

How many carbon atoms in a 3.25*"carat"3.25*"carat" diamond?