A mass of $30 \cdot g$ $30g$ of $K N O_{3}$ $KNO_3$ was dissolved in water to give a $0.30 \cdot m o l \cdot L^{- 1}$ $0.30mol*L^-1$ solution. What volume of water was used?

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A mass of $30 \cdot g$ $30g$ of $K N O_{3}$ $KNO_3$ was dissolved in water to give a $0.30 \cdot m o l \cdot L^{- 1}$ $0.30mol*L^-1$ solution. What volume of water was used?

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Answer 1 · 2018-01-07T07:53:10

Approx. $1 \cdot L$ $1*L$

Explanation:

We use the relationship...

$Concentration = \frac{Moles of solute}{Volume of solution....}$ $"Concentration"="Moles of solute"/"Volume of solution...."$

And thus we get ..... $Volume of solution = \frac{Moles of solute}{Concentration}$ $"Volume of solution"="Moles of solute"/"Concentration"$

$= \frac{\frac{30.0 \cdot g}{101.1 \cdot g \cdot m o l^{- 1}}}{0.30 \cdot m o l \cdot L^{- 1}} = 1.00 \cdot \frac{1}{L^{- 1}} = \frac{1}{\frac{1}{L}} = 1.00 \cdot L$ $=((30.0*g)/(101.1*g*mol^-1))/(0.30*mol*L^-1)=1.00*1/L^-1=1/(1/L)=1.00*L$

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A mass of $30 \cdot g$ $30g$ of $K N O_{3}$ $KNO_3$ was dissolved in water to give a $0.30 \cdot m o l \cdot L^{- 1}$ $0.30mol*L^-1$ solution. What volume of water was used?

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A mass of 30*g30⋅g30*g of KNO_3KNO3KNO_3 was dissolved in water to give a 0.30*mol*L^-10.30⋅mol⋅L−10.30*mol*L^-1 solution. What volume of water was used?

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Explanation:

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A mass of $30 \cdot g$ $30g$ of $K N O_{3}$ $KNO_3$ was dissolved in water to give a $0.30 \cdot m o l \cdot L^{- 1}$ $0.30mol*L^-1$ solution. What volume of water was used?