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Answer 1 · 2016-10-18T03:03:08

The temperature change is $"107"^@"C"$ .

Specific heat is the amount of heat necessary to increase the temperature of 1.00 gram of a substance by $"1.00"^@"C"$ .

The equation to use in order to answer this question is:

$Q=mcDeltaT$ , where $Q$ is energy, $m$ is mass, $c$ is specific heat, and $DeltaT$ is change in temperature.

Known
$m="2.51 g"$
$c=0.382 "J"/("g"^@"C")$
$Q="102.53 J"$

Unknown
$DeltaT$

Solution
Rearrange the equation to isolate $DeltaT$ .

$Q=mcDeltaT$

$DeltaT=Q/(mc)$

$DeltaT=(102.53cancel"J")/(2.51cancel"g"*0.382 cancel"J"/(cancel"g"^@"C")$ $=$ $"107"^@"C"$