Question

Question #79ed9

Answer 1

The temperature change is `"107"^@"C"`.

Explanation:

Specific heat is the amount of heat necessary to increase the temperature of 1.00 gram of a substance by `"1.00"^@"C"`.

The equation to use in order to answer this question is:

`Q=mcDeltaT`, where `Q` is energy, `m` is mass, `c` is specific heat, and `DeltaT` is change in temperature.

Known
`m="2.51 g"`
`c=0.382 "J"/("g"^@"C")`
`Q="102.53 J"`

Unknown
`DeltaT`

Solution
Rearrange the equation to isolate `DeltaT`.

`Q=mcDeltaT`

`DeltaT=Q/(mc)`

`DeltaT=(102.53cancel"J")/(2.51cancel"g"*0.382 cancel"J"/(cancel"g"^@"C")` `=` `"107"^@"C"`