Question #28af1

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Question #28af1

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Answer 1 · 2016-10-25T08:38:03

$5.6 \times 6.022 \times 10^{23} atoms$ $5.6 xx 6.022 xx 10^23"atoms"$

Explanation:

A mole of ${PCl}_{3}$ $"PCl"_3$ contains

one mole of $P$ $"P"$

three moles of $Cl$ $"Cl"$

Therefore, you get a total of 4 moles of atoms per mole of ${PCl}_{3}$ $"PCl"_3$ . This means that $1.4$ $1.4$ moles of ${PCl}_{3}$ $"PCl"_3$ contain

$1.4 \times 4 = 5.6 moles of atoms$ $1.4 xx 4 = "5.6 moles of atoms"$

Each mole of atoms contains Avogadro's number, $6.022 \times 10^{23}$ $6.022 xx 10^23$ , of atoms. Therefore, the sample contains

$5.6 \times 6.022 \times 10^{23} atoms$ $5.6 xx 6.022 xx 10^23"atoms"$ .

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Question #28af1

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