Question #66789

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Answer 1 · 2017-01-16T01:58:28

$y = \frac{4 + m}{5 + m} \Rightarrow m = \frac{4 - 5 y}{y - 1}$ $y=(4+m)/(5+m) => m=(4-5y)/(y-1)$

$y = \frac{4 + m}{5 + m}$ $y=(4+m)/(5+m)$ Our original expression

$\Leftrightarrow$ $<=>$

$y (5 + m) = 4 + m$ $y(5+m)=4+m$ Divide both sides by 5+m

$\Leftrightarrow$ $<=>$

$5 y + m y = 4 + m$ $5y+my=4+m$ Distribute y

$\Leftrightarrow$ $<=>$

$5 y + m y - m = 4$ $5y+my-m=4$ Subtract m from both sides

$\Leftrightarrow$ $<=>$

$m y - m = 4 - 5 y$ $my-m=4-5y$ Subtract 5y from both sides

$\Leftrightarrow$ $<=>$

$m (y - 1) = 4 - 5 y$ $m(y-1)=4-5y$ Factor for m on the left side

$\Leftrightarrow$ $<=>$

$m = \frac{4 - 5 y}{y - 1}$ $m=(4-5y)/(y-1)$

Divide both sides by y-1 leaving the rearrangement for m